x^2-16=(x-4)(x+4)

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Solution for x^2-16=(x-4)(x+4) equation:


Simplifying
x2 + -16 = (x + -4)(x + 4)

Reorder the terms:
-16 + x2 = (x + -4)(x + 4)

Reorder the terms:
-16 + x2 = (-4 + x)(x + 4)

Reorder the terms:
-16 + x2 = (-4 + x)(4 + x)

Multiply (-4 + x) * (4 + x)
-16 + x2 = (-4(4 + x) + x(4 + x))
-16 + x2 = ((4 * -4 + x * -4) + x(4 + x))
-16 + x2 = ((-16 + -4x) + x(4 + x))
-16 + x2 = (-16 + -4x + (4 * x + x * x))
-16 + x2 = (-16 + -4x + (4x + x2))

Combine like terms: -4x + 4x = 0
-16 + x2 = (-16 + 0 + x2)
-16 + x2 = (-16 + x2)

Add '16' to each side of the equation.
-16 + 16 + x2 = -16 + 16 + x2

Combine like terms: -16 + 16 = 0
0 + x2 = -16 + 16 + x2
x2 = -16 + 16 + x2

Combine like terms: -16 + 16 = 0
x2 = 0 + x2
x2 = x2

Add '-1x2' to each side of the equation.
x2 + -1x2 = x2 + -1x2

Combine like terms: x2 + -1x2 = 0
0 = x2 + -1x2

Combine like terms: x2 + -1x2 = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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